What is 4y^2-49x^2-392x+16y-964=0 ?

The solution to 4y^2-49x^2-392x+16y-964=0 is Hyperbola with (h,k)=(-4,-2),a=7,b=2

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4y^2-49x^2-392x+16y-964=0

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

(h, k) = (- 4, - 2), a = 7, b = 2

Solution steps

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

Rewrite

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{7 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 2), a = 7, b = 2

x^{2} - 2 y^{2} = 4

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

\frac{( y - 2 ) ^{2}}{16} - \frac{( x + 1 ) ^{2}}{144} = 1

16 x^{2} - 160 x - 16 y^{2} - 128 y - 112 = 0

[f (x)]^{2} = 3 x^{2} - x + 2

What is 4y^2-49x^2-392x+16y-964=0 ?
The solution to 4y^2-49x^2-392x+16y-964=0 is Hyperbola with (h,k)=(-4,-2),a=7,b=2