What is ((x^2}{16})-(\frac{y^2)/9)=1 ?

The solution to ((x^2}{16})-(\frac{y^2)/9)=1 is Hyperbola with (h,k)=(0,0),a=4,b=3

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((x^2}{16})-(\frac{y^2)/9)=1

(\frac{x ^{2}}{16}) - (\frac{y ^{2}}{9}) = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 3

\frac{x ^{2}}{4} - \frac{( Y ( x ) + 1 ) ^{2}}{16} = 1

6 x^{2} - 5 y^{2} - 24 x + 10 y - 11 = 0

y^{2} - x^{2} = - 1

2 x^{2} - y^{2} = 2

\frac{( x - 1 ) ^{2}}{4} - (y + 3)^{2} = 1

What is ((x^2}{16})-(\frac{y^2)/9)=1 ?
The solution to ((x^2}{16})-(\frac{y^2)/9)=1 is Hyperbola with (h,k)=(0,0),a=4,b=3