What is ((x-2)^2)/9-(y^2)/4 =1 ?

The solution to ((x-2)^2)/9-(y^2)/4 =1 is Hyperbola with (h,k)=(2,0),a=3,b=2

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((x-2)^2)/9-(y^2)/4 =1

\frac{( x - 2 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

(h, k) = (2, 0), a = 3, b = 2

Solution steps

\frac{( x - 2 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 0), a = 3, b = 2

(\frac{x + 1}{25})^{2} - (\frac{y - 4}{144})^{2} = 1

\frac{x ^{2}}{64} - \frac{y ^{2}}{100} = 1

y^{2} = (x - 2)^{2} - 1

y^{2} - x^{2} = 100

y^{2} - x^{2} + 5 x - 4 y + 3 = 0

What is ((x-2)^2)/9-(y^2)/4 =1 ?
The solution to ((x-2)^2)/9-(y^2)/4 =1 is Hyperbola with (h,k)=(2,0),a=3,b=2