What is (x^2)/9-(y^2)/(40)=1 ?

The solution to (x^2)/9-(y^2)/(40)=1 is Hyperbola with (h,k)=(0,0),a=3,b=2sqrt(10)

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(x^2)/9-(y^2)/(40)=1

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

(h, k) = (0, 0), a = 3, b = 210

Solution steps

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

Rewrite

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 10 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 210

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

y^{2} = x^{2} - 4

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = - 1

(y - 1)^{2} - x^{2} + 1 = 50

y^{2} = x^{2} + 2

What is (x^2)/9-(y^2)/(40)=1 ?
The solution to (x^2)/9-(y^2)/(40)=1 is Hyperbola with (h,k)=(0,0),a=3,b=2sqrt(10)