What is ((x+4)^2)/4-((y+3)^2)/4 =1 ?

The solution to ((x+4)^2)/4-((y+3)^2)/4 =1 is Hyperbola with (h,k)=(-4,-3),a=2,b=2

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((x+4)^2)/4-((y+3)^2)/4 =1

\frac{( x + 4 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{4} = 1

(h, k) = (- 4, - 3), a = 2, b = 2

Solution steps

\frac{( x + 4 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 3), a = 2, b = 2

24 x^{2} - 9 y^{2} = 216

4 x^{2} - 6 y^{2} = 9

4 x^{2} - 2 x - 4 y^{2} - 4 = 0

3 x^{2} - y^{2} = 3

y^{2} - 16 x^{2} + 64 x - 208 = 0

What is ((x+4)^2)/4-((y+3)^2)/4 =1 ?
The solution to ((x+4)^2)/4-((y+3)^2)/4 =1 is Hyperbola with (h,k)=(-4,-3),a=2,b=2