What is (x^2)/(2^2)-(y^2)/(3^2)=1 ?

The solution to (x^2)/(2^2)-(y^2)/(3^2)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3

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(x^2)/(2^2)-(y^2)/(3^2)=1

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

25 x^{2} + 246 x - 25 y^{2} - 13 y = 233

9 x^{2} - 4 y^{2} - 18 x + 16 y - 43 = 0

16 x^{2} - 9 y^{2} - 144 = 0

\frac{( x - 4 ) ^{2}}{2} - \frac{( y - 3 ) ^{2}}{1} = 1

\frac{( y - 7 ) ^{2}}{64} - \frac{( x - 3 ) ^{2}}{16} = 1

What is (x^2)/(2^2)-(y^2)/(3^2)=1 ?
The solution to (x^2)/(2^2)-(y^2)/(3^2)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3