What is (x+2)^2-y^2=8 ?

The solution to (x+2)^2-y^2=8 is Hyperbola with (h,k)=(-2,0),a=2sqrt(2),b=2sqrt(2)

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(x+2)^2-y^2=8

(x + 2)^{2} - y^{2} = 8

(h, k) = (- 2, 0), a = 22, b = 22

Solution steps

(x + 2)^{2} - y^{2} = 8

Rewrite

(x + 2)^{2} - y^{2} = 8

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 0), a = 22, b = 22

x^{2} - y^{2} = - 1

- 4 x^{2} + y^{2} - 2 y = 3

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0

- 9 x^{2} + 4 y^{2} = 36

- 8 x^{2} + 2 y^{2} - 12 = 0

What is (x+2)^2-y^2=8 ?
The solution to (x+2)^2-y^2=8 is Hyperbola with (h,k)=(-2,0),a=2sqrt(2),b=2sqrt(2)