What is ((x+2)^2)/9-((y-1)^2)/(16)=1 ?

The solution to ((x+2)^2)/9-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(-2,1),a=3,b=4

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((x+2)^2)/9-((y-1)^2)/(16)=1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

(h, k) = (- 2, 1), a = 3, b = 4

Solution steps

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 3, b = 4

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

4 x^{2} - 8 y^{2} = 3

y^{2} = x^{2} + 9

x^{2} - y^{2} + 2 x - y = 0

y^{2} - 4 y - 4 x^{2} + 8 x - 4 = 0

What is ((x+2)^2)/9-((y-1)^2)/(16)=1 ?
The solution to ((x+2)^2)/9-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(-2,1),a=3,b=4