What is ((x-3)^2)/(25)-((y+1)^2)/(25)=1 ?

The solution to ((x-3)^2)/(25)-((y+1)^2)/(25)=1 is Hyperbola with (h,k)=(3,-1),a=5,b=5

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((x-3)^2)/(25)-((y+1)^2)/(25)=1

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 1 ) ^{2}}{25} = 1

(h, k) = (3, - 1), a = 5, b = 5

Solution steps

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{5 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 1), a = 5, b = 5

8 x^{2} - 2 y^{2} - 4 x - 6 y + 15 = 0

x^{2} - 4 y^{2} = 16

x^{2} - 4 y^{2} - 2 x - 40 y - 103 = 0

y^{2} - x^{2} = 16

(x - 1)^{2} - y^{2} = 1

What is ((x-3)^2)/(25)-((y+1)^2)/(25)=1 ?
The solution to ((x-3)^2)/(25)-((y+1)^2)/(25)=1 is Hyperbola with (h,k)=(3,-1),a=5,b=5