What is the axis 16x^2+9y^2-144=0 ?

The axis 16x^2+9y^2-144=0 is semi-major axis b=4, semi-minor axis a=3

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axis 16x^2+9y^2-144=0

axis

16 x^{2} + 9 y^{2} - 144 = 0

semi - major axis b = 4, semi - minor axis a = 3

Solution steps

16 x^{2} + 9 y^{2} - 144 = 0

Rewrite

16 x^{2} + 9 y^{2} - 144 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 3

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 9 ) ^{2}}{25} = 1

\frac{x ^{2}}{56} + \frac{y ^{2}}{36} = 1

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{16} = 1

3 x^{2} + 7 y^{2} = 63

What is the axis 16x^2+9y^2-144=0 ?
The axis 16x^2+9y^2-144=0 is semi-major axis b=4, semi-minor axis a=3