What is the axis (x^2)/9+(y-1)^2=1 ?

The axis (x^2)/9+(y-1)^2=1 is semi-major axis a=3, semi-minor axis b=1

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axis (x^2)/9+(y-1)^2=1

axis

\frac{x ^{2}}{9} + (y - 1)^{2} = 1

semi - major axis a = 3, semi - minor axis b = 1

Solution steps

\frac{x ^{2}}{9} + (y - 1)^{2} = 1

Rewrite

\frac{x ^{2}}{9} + (y - 1)^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 1), a = 3, b = 1

9 x^{2} + 16 y^{2} - 144 = 0

x^{2} + 4 y^{2} = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

16 x^{2} + 4 y^{2} = 25

4 x^{2} + 9 y^{2} - 36 = 0

What is the axis (x^2)/9+(y-1)^2=1 ?
The axis (x^2)/9+(y-1)^2=1 is semi-major axis a=3, semi-minor axis b=1