What is the axis 9x^2+16y^2-144=0 ?

The axis 9x^2+16y^2-144=0 is semi-major axis a=4, semi-minor axis b=3

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axis 9x^2+16y^2-144=0

axis

9 x^{2} + 16 y^{2} - 144 = 0

semi - major axis a = 4, semi - minor axis b = 3

Solution steps

9 x^{2} + 16 y^{2} - 144 = 0

Rewrite

9 x^{2} + 16 y^{2} - 144 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

x^{2} + 4 y^{2} = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

16 x^{2} + 4 y^{2} = 25

4 x^{2} + 9 y^{2} - 36 = 0

5 x^{2} + 9 y^{2} - 10 x - 36 y = 4

What is the axis 9x^2+16y^2-144=0 ?
The axis 9x^2+16y^2-144=0 is semi-major axis a=4, semi-minor axis b=3