What is the axis ((x-2)^2}{36}+\frac{(y+5)^2)/9 =1 ?

The axis ((x-2)^2}{36}+\frac{(y+5)^2)/9 =1 is semi-major axis a=6, semi-minor axis b=3

Popular >

axis ((x-2)^2}{36}+\frac{(y+5)^2)/9 =1

axis

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

semi - major axis a = 6, semi - minor axis b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{6 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 5), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 5), a = 6, b = 3

25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

x^{2} + y^{2} - y = 0

16 x^{2} + y^{2} - 64 x + 8 y + 16 = 0

3 x^{2} + y^{2} + 2 x - 6 y = 3

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

What is the axis ((x-2)^2}{36}+\frac{(y+5)^2)/9 =1 ?
The axis ((x-2)^2}{36}+\frac{(y+5)^2)/9 =1 is semi-major axis a=6, semi-minor axis b=3