What is the axis (x^2)/(81)+(y^2)/(64)=1 ?

The axis (x^2)/(81)+(y^2)/(64)=1 is semi-major axis a=9, semi-minor axis b=8

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axis (x^2)/(81)+(y^2)/(64)=1

axis

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

semi - major axis a = 9, semi - minor axis b = 8

Solution steps

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 9, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 9, b = 8

41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

x^{2} + y^{2} - 2 y = 0

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

\frac{( x - 2 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

What is the axis (x^2)/(81)+(y^2)/(64)=1 ?
The axis (x^2)/(81)+(y^2)/(64)=1 is semi-major axis a=9, semi-minor axis b=8