What is f(x)(a-3)=-x^2+5 ?

The solution to f(x)(a-3)=-x^2+5 is Parabola with (h,k)=(0,-5/(-a+3)),p=(-a+3)/4

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f(x)(a-3)=-x^2+5

f (x) (a - 3) = - x^{2} + 5

(h, k) = (0, - \frac{5}{- a + 3}), p = \frac{- a + 3}{4}

Solution steps

y (a - 3) = - x^{2} + 5

Rewrite

y (a - 3) = - x^{2} + 5

in the standard form:

4 \cdot \frac{- a + 3}{4} (y - (- \frac{5}{- a + 3})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{5}{- a + 3}), p = \frac{- a + 3}{4}

y + 4 x = x^{2}

y^{2} - 12 x + 8 y = - 100

x = (y + 15)^{2} - 1

8 r^{2} + 22 t + 15 = 0

(x - 15)^{2} = - 2 (y - 6)

What is f(x)(a-3)=-x^2+5 ?
The solution to f(x)(a-3)=-x^2+5 is Parabola with (h,k)=(0,-5/(-a+3)),p=(-a+3)/4