What is the eccentricity 16x^2+4y^2+96x-24y+116=0 ?

The eccentricity 16x^2+4y^2+96x-24y+116=0 is (sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity 16x^2+4y^2+96x-24y+116=0

eccentricity

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

\frac{3}{2}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0 :

Ellipse with center

(h, k) = (- 3, 3), b = 4, a = 2

= \frac{4 ^{2} - 2 ^{2}}{4}

\frac{4 ^{2} - 2 ^{2}}{4} = \frac{3}{2}

= \frac{3}{2}

x^{2} + 4 y^{2} - 4 x - 8 y - 92 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

x^{2} + \frac{y ^{2}}{4} = 1

x^{2} + 4 y^{2} = 46

+ x^{2} = 4 y - 2 y^{2}

What is the eccentricity 16x^2+4y^2+96x-24y+116=0 ?
The eccentricity 16x^2+4y^2+96x-24y+116=0 is (sqrt(3))/2