What is the eccentricity (x^2)/(169)+(y^2)/(144)=1 ?

The eccentricity (x^2)/(169)+(y^2)/(144)=1 is 5/13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/(169)+(y^2)/(144)=1

eccentricity

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

\frac{5}{13}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 13, b = 12

= \frac{1 3 ^{2} - 1 2 ^{2}}{13}

\frac{1 3 ^{2} - 1 2 ^{2}}{13} = \frac{5}{13}

= \frac{5}{13}

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{3} = 1

9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

4 x^{2} + 25 y^{2} - 40 x + 150 y + 225 = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

What is the eccentricity (x^2)/(169)+(y^2)/(144)=1 ?
The eccentricity (x^2)/(169)+(y^2)/(144)=1 is 5/13