What is the eccentricity 4x^2+49y^2=196 ?

The eccentricity 4x^2+49y^2=196 is (3sqrt(5))/7

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eccentricity 4x^2+49y^2=196

eccentricity

4 x^{2} + 49 y^{2} = 196

\frac{3 5}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

4 x^{2} + 49 y^{2} = 196 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 2

= \frac{7 ^{2} - 2 ^{2}}{7}

\frac{7 ^{2} - 2 ^{2}}{7} = \frac{3 5}{7}

= \frac{3 5}{7}

\frac{( x + 4 ) ^{2}}{\frac{25}{4}} + (y - 6)^{2} = 1

7 x^{2} + 9 y^{2} = 63

4 xx + 9 yy = 36

25 x^{2} - 12 y + y^{2} - 26 y = - 11

5 x^{2} + 2 y^{2} = 50

What is the eccentricity 4x^2+49y^2=196 ?
The eccentricity 4x^2+49y^2=196 is (3sqrt(5))/7