What is the eccentricity (x^2)/(169)+(y^2)/(25)=1 ?

The eccentricity (x^2)/(169)+(y^2)/(25)=1 is 12/13

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eccentricity (x^2)/(169)+(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

\frac{12}{13}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 13, b = 5

= \frac{1 3 ^{2} - 5 ^{2}}{13}

\frac{1 3 ^{2} - 5 ^{2}}{13} = \frac{12}{13}

= \frac{12}{13}

16 x^{2} + 9 y^{2} + 160 x - 72 y + 544 = 144

\frac{x ^{2}}{25} + \frac{y ^{2}}{64} = 1

x^{2} + 9 y^{2} + 16 x + 18 y + 64 = 0

x^{2} + 42 y^{2} = 42

\frac{( x - 4 ) ^{2}}{2} + \frac{( y - 4 ) ^{2}}{3} = 1

What is the eccentricity (x^2)/(169)+(y^2)/(25)=1 ?
The eccentricity (x^2)/(169)+(y^2)/(25)=1 is 12/13