What is the eccentricity (x^2}{16}+\frac{y^2)/4 =1 ?

The eccentricity (x^2}{16}+\frac{y^2)/4 =1 is (sqrt(3))/2

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eccentricity (x^2}{16}+\frac{y^2)/4 =1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

\frac{3}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 2

= \frac{4 ^{2} - 2 ^{2}}{4}

\frac{4 ^{2} - 2 ^{2}}{4} = \frac{3}{2}

= \frac{3}{2}

\frac{( x - 4 ) ^{2}}{5} + \frac{( y - 2 ) ^{2}}{4} = 1

49 x^{2} - 98 x + 64 y^{2} + 256 y - 2831 = 0

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{25} = 1

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

4 x^{2} + 32 x + 25 y^{2} - 250 y + 589 = 0

What is the eccentricity (x^2}{16}+\frac{y^2)/4 =1 ?
The eccentricity (x^2}{16}+\frac{y^2)/4 =1 is (sqrt(3))/2