What is the eccentricity (x^2)/4+(y^2)/(3.2)=1 ?

The eccentricity (x^2)/4+(y^2)/(3.2)=1 is 0.4472135955

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eccentricity (x^2)/4+(y^2)/(3.2)=1

eccentricity

\frac{x ^{2}}{4} + \frac{y ^{2}}{3.2} = 1

0.4472135955

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{3.2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 3.2

= \frac{2 ^{2} - ( 3.2 ) ^{2}}{2}

\frac{2 ^{2} - ( 3.2 ) ^{2}}{2} = 0.4472135955

= 0.4472135955

9 x^{2} + 7 y^{2} = 63

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

x^{2} + 16 y^{2} - 64 = 0

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

2 x^{2} + 7 y^{2} = 14

What is the eccentricity (x^2)/4+(y^2)/(3.2)=1 ?
The eccentricity (x^2)/4+(y^2)/(3.2)=1 is 0.4472135955