What is the eccentricity (x^2)/(25)+(y^2)/(36)=1 ?

The eccentricity (x^2)/(25)+(y^2)/(36)=1 is (sqrt(11))/6

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eccentricity (x^2)/(25)+(y^2)/(36)=1

eccentricity

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

\frac{11}{6}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 5

= \frac{6 ^{2} - 5 ^{2}}{6}

\frac{6 ^{2} - 5 ^{2}}{6} = \frac{11}{6}

= \frac{11}{6}

4 x^{2} + y^{2} = 16

x^{2} + y^{2} - 6 x - 8 y = 50

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1

\frac{x ^{2}}{4} + y^{2} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

What is the eccentricity (x^2)/(25)+(y^2)/(36)=1 ?
The eccentricity (x^2)/(25)+(y^2)/(36)=1 is (sqrt(11))/6