What is the eccentricity (x^2)/9+(y^2)/4 =1 ?

The eccentricity (x^2)/9+(y^2)/4 =1 is (sqrt(5))/3

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eccentricity (x^2)/9+(y^2)/4 =1

eccentricity

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

\frac{5}{3}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 2

= \frac{3 ^{2} - 2 ^{2}}{3}

\frac{3 ^{2} - 2 ^{2}}{3} = \frac{5}{3}

= \frac{5}{3}

x^{2} + 2 y^{2} = 2

+ 36 x^{2} + y^{2} = 36

(x - 1)^{2} + (y - 2)^{2} = 30

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

(\frac{x - 1}{4})^{2} + (\frac{y + 2}{3})^{2} = 1

What is the eccentricity (x^2)/9+(y^2)/4 =1 ?
The eccentricity (x^2)/9+(y^2)/4 =1 is (sqrt(5))/3