What is the center 4x^2+9y^2=144 ?

The center 4x^2+9y^2=144 is (0,0)

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center 4x^2+9y^2=144

center

4 x^{2} + 9 y^{2} = 144

(0, 0)

Solution steps

4 x^{2} + 9 y^{2} = 144

Rewrite

4 x^{2} + 9 y^{2} = 144

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

And the center is:

(0, 0)

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

x^{2} - 8 x + 8 y^{2} + 12 y = 0

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

9 x^{2} + 25 y^{2} = 225

x^{2} + y^{2} + 2 x - 2 x + 6 y = 0