What is the center (x^2)/(16)+((y-1)^2)/(36)=1 ?

The center (x^2)/(16)+((y-1)^2)/(36)=1 is (0,1)

Popular >

center (x^2)/(16)+((y-1)^2)/(36)=1

center

\frac{x ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

(0, 1)

Solution steps

\frac{x ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 1 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 4, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 6, a = 4

And the center is:

(0, 1)

\frac{x ^{2}}{9} + \frac{( y + 5 ) ^{2}}{25} = 1

2 x^{2} + 4 x = 19 - 3 y^{2}

9 x^{2} + 49 y^{2} + 18 x + 294 y - 9 = 0

\frac{( x - 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

4 x^{2} + y^{2} - 5 = 0

What is the center (x^2)/(16)+((y-1)^2)/(36)=1 ?
The center (x^2)/(16)+((y-1)^2)/(36)=1 is (0,1)