What is the center 2x^2+4x=19-3y^2 ?

The center 2x^2+4x=19-3y^2 is (-1,0)

Popular >

center 2x^2+4x=19-3y^2

center

2 x^{2} + 4 x = 19 - 3 y^{2}

(- 1, 0)

Solution steps

2 x^{2} + 4 x = 19 - 3 y^{2}

Rewrite

2 x^{2} + 4 x = 19 - 3 y^{2}

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( \frac{21}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = \frac{21}{2}, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), a = \frac{21}{2}, b = 7

And the center is:

(- 1, 0)

9 x^{2} + 49 y^{2} + 18 x + 294 y - 9 = 0

\frac{( x - 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

4 x^{2} + y^{2} - 5 = 0

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

\frac{( x + 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1