What is the center 2x^2+y^2+12x-6y+26=0 ?

The center 2x^2+y^2+12x-6y+26=0 is (-3,3)

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center 2x^2+y^2+12x-6y+26=0

center

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

(- 3, 3)

Solution steps

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

Rewrite

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - 3 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 3), a = \frac{1}{2}, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, 3), b = 1, a = \frac{1}{2}

And the center is:

(- 3, 3)

x^{2} + y^{2} - 8 y = 0

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{5} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

6 x^{2} + 8 y^{2} + 12 x - 32 y = 178

What is the center 2x^2+y^2+12x-6y+26=0 ?
The center 2x^2+y^2+12x-6y+26=0 is (-3,3)