center (x^2)/(64)+(y^2)/(100)=1

Lösung

center

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

(0, 0)

Schritte zur Lösung

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 10, a = 8

And the center is:

(0, 0)

ce n t er 9 x^{2} + 16 y^{2} - 54 x + 64 y + 1 = 0

ce n t er 9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

ce n t er x^{2} + y^{2} - 4 y = 0

ce n t er \frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

ce n t er 12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0