What is the foci 2x^2+y^2+12x-2y+11=0 ?

The foci 2x^2+y^2+12x-2y+11=0 is (-3,3),(-3,-1)

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foci 2x^2+y^2+12x-2y+11=0

foci

2 x^{2} + y^{2} + 12 x - 2 y + 11 = 0

(- 3, 3), (- 3, - 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

2 x^{2} + y^{2} + 12 x - 2 y + 11 = 0 :

Ellipse with center

(h, k) = (- 3, 1), b = 22, a = 2

(- 3, 1 + c), (- 3, 1 - c)

Compute

c :

c = (22)^{2} - 2^{2} : 2

(- 3, 1 + 2), (- 3, 1 - 2)

Refine

(- 3, 3), (- 3, - 1)

16 x^{2} + 9 y^{2} + 64 x - 80 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{36} = 1

What is the foci 2x^2+y^2+12x-2y+11=0 ?
The foci 2x^2+y^2+12x-2y+11=0 is (-3,3),(-3,-1)