What is the foci (x^2)/(0.383^2)+(y^2)/(0.3748^2)=1 ?

The foci (x^2)/(0.383^2)+(y^2)/(0.3748^2)=1 is (0.07882…,0),(-0.07882…,0)

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foci (x^2)/(0.383^2)+(y^2)/(0.3748^2)=1

foci

\frac{x ^{2}}{0.38 3 ^{2}} + \frac{y ^{2}}{0.374 8 ^{2}} = 1

(0.07882 \dots, 0), (- 0.07882 \dots, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{0.38 3 ^{2}} + \frac{y ^{2}}{0.374 8 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 0.383, b = 0.3748

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 0.38 3^{2} - 0.374 8^{2} : 0.07882 \dots

(0 + 0.07882 \dots, 0), (0 - 0.07882 \dots, 0)

Refine

(0.07882 \dots, 0), (- 0.07882 \dots, 0)

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{4} = 1

25 x^{2} + 16 y^{2} - 150 x - 32 y - 159 = 0

\frac{( x + 6 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

9 x^{2} + y^{2} + 18 x - 4 y + 4 = 0

What is the foci (x^2)/(0.383^2)+(y^2)/(0.3748^2)=1 ?
The foci (x^2)/(0.383^2)+(y^2)/(0.3748^2)=1 is (0.07882…,0),(-0.07882…,0)