What is the foci 4(x-4)^2+9y^2=36 ?

The foci 4(x-4)^2+9y^2=36 is (4+sqrt(5),0),(4-sqrt(5),0)

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foci 4(x-4)^2+9y^2=36

foci

4 (x - 4)^{2} + 9 y^{2} = 36

(4 + 5, 0), (4 - 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 (x - 4)^{2} + 9 y^{2} = 36 :

Ellipse with center

(h, k) = (4, 0), a = 3, b = 2

(4 + c, 0), (4 - c, 0)

Compute

c :

c = 3^{2} - 2^{2} : 5

(4 + 5, 0), (4 - 5, 0)

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 7 ) ^{2}}{81} = 1

\frac{x ^{2}}{67} + \frac{y ^{2}}{57} = 1

4 x^{2} + 16 y^{2} = 64

\frac{( x + 4 ) ^{2}}{22} + \frac{( y + 3 ) ^{2}}{26} = 1

+ 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

What is the foci 4(x-4)^2+9y^2=36 ?
The foci 4(x-4)^2+9y^2=36 is (4+sqrt(5),0),(4-sqrt(5),0)