What is the foci 9x^2+25y^2+108x-200y+499=0 ?

The foci 9x^2+25y^2+108x-200y+499=0 is (-2,4),(-10,4)

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foci 9x^2+25y^2+108x-200y+499=0

foci

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0

(- 2, 4), (- 10, 4)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0 :

Ellipse with center

(h, k) = (- 6, 4), a = 5, b = 3

(- 6 + c, 4), (- 6 - c, 4)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 6 + 4, 4), (- 6 - 4, 4)

Refine

(- 2, 4), (- 10, 4)

\frac{( x - 6 ) ^{2}}{49} + \frac{( y - 6 ) ^{2}}{36} = 1

8 x^{2} + 4 y^{2} + 16 x - 12 y - 15 = 0

\frac{25 x ^{2}}{4} - 50 x + 100 y^{2} + 800 y + 1075 = 0

5 x^{2} + y^{2} = 5

8 x^{2} + 9 y^{2} - 72 = 0

What is the foci 9x^2+25y^2+108x-200y+499=0 ?
The foci 9x^2+25y^2+108x-200y+499=0 is (-2,4),(-10,4)