What is the foci ((x-6)^2)/(49)+((y-6)^2)/(36)=1 ?

The foci ((x-6)^2)/(49)+((y-6)^2)/(36)=1 is (6+sqrt(13),6),(6-sqrt(13),6)

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foci ((x-6)^2)/(49)+((y-6)^2)/(36)=1

foci

\frac{( x - 6 ) ^{2}}{49} + \frac{( y - 6 ) ^{2}}{36} = 1

(6 + 13, 6), (6 - 13, 6)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 6 ) ^{2}}{49} + \frac{( y - 6 ) ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (6, 6), a = 7, b = 6

(6 + c, 6), (6 - c, 6)

Compute

c :

c = 7^{2} - 6^{2} : 13

(6 + 13, 6), (6 - 13, 6)

8 x^{2} + 4 y^{2} + 16 x - 12 y - 15 = 0

\frac{25 x ^{2}}{4} - 50 x + 100 y^{2} + 800 y + 1075 = 0

5 x^{2} + y^{2} = 5

8 x^{2} + 9 y^{2} - 72 = 0

\frac{y ^{2}}{169} + \frac{x ^{2}}{25} = 1

What is the foci ((x-6)^2)/(49)+((y-6)^2)/(36)=1 ?
The foci ((x-6)^2)/(49)+((y-6)^2)/(36)=1 is (6+sqrt(13),6),(6-sqrt(13),6)