What is the foci (x^2)/(625)+(y^2)/(400)=1 ?

The foci (x^2)/(625)+(y^2)/(400)=1 is (15,0),(-15,0)

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foci (x^2)/(625)+(y^2)/(400)=1

foci

\frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1

(15, 0), (- 15, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 25, b = 20

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2 5^{2} - 2 0^{2} : 15

(0 + 15, 0), (0 - 15, 0)

Refine

(15, 0), (- 15, 0)

\frac{( y + 4 ) ^{2}}{49} + \frac{( x - 9 ) ^{2}}{25} = 1

1 x^{2} + 3 y^{2} + 9 x + 8 y - 3 = 0

\frac{( x - 5 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{49} = 1

\frac{( x + 5 ) ^{2}}{4} + \frac{( y + 5 ) ^{2}}{25} = 1

4 x^{2} + 9 y^{2} + 16 x + 18 y - 11 = 0

What is the foci (x^2)/(625)+(y^2)/(400)=1 ?
The foci (x^2)/(625)+(y^2)/(400)=1 is (15,0),(-15,0)