What is the foci ((x+0)^2)/(100)+((y+0)^2)/(64)=1 ?

The foci ((x+0)^2)/(100)+((y+0)^2)/(64)=1 is (6,0),(-6,0)

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foci ((x+0)^2)/(100)+((y+0)^2)/(64)=1

foci

\frac{( x + 0 ) ^{2}}{100} + \frac{( y + 0 ) ^{2}}{64} = 1

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 0 ) ^{2}}{100} + \frac{( y + 0 ) ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

2205 = 180 x^{2} + 196 y^{2}

\frac{x ^{2}}{0.38 1 ^{2}} + \frac{y ^{2}}{0.372 8 ^{2}} = 1

25 x^{2} + 9 y^{2} + 150 x = 0

4 x^{2} + y^{2} - 4 y = 0

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

What is the foci ((x+0)^2)/(100)+((y+0)^2)/(64)=1 ?
The foci ((x+0)^2)/(100)+((y+0)^2)/(64)=1 is (6,0),(-6,0)