What is the foci-((y-1)^2}{144}-\frac{(x+2)^2)/9 =1 ?

The foci-((y-1)^2}{144}-\frac{(x+2)^2)/9 =1 is (-2,1+3sqrt(15)),(-2,1-3sqrt(15))

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foci-((y-1)^2}{144}-\frac{(x+2)^2)/9 =1

foci

- \frac{( y - 1 ) ^{2}}{144} - \frac{( x + 2 ) ^{2}}{9} = 1

(- 2, 1 + 315), (- 2, 1 - 315)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

- \frac{( y - 1 ) ^{2}}{144} - \frac{( x + 2 ) ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (- 2, 1), b = 12, a = 3

(- 2, 1 + c), (- 2, 1 - c)

Compute

c :

c = 1 2^{2} - 3^{2} : 315

(- 2, 1 + 315), (- 2, 1 - 315)

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{1} = 1

x^{2} + 4 y^{2} + 10 x + 9 y - 10 = 0

y^{2} = 1 - 4 x^{2}

16 x^{2} + 25 y^{2} = 1600

5 x^{2} + 9 y^{2} - 20 x - 18 y - 16 = 0

What is the foci-((y-1)^2}{144}-\frac{(x+2)^2)/9 =1 ?
The foci-((y-1)^2}{144}-\frac{(x+2)^2)/9 =1 is (-2,1+3sqrt(15)),(-2,1-3sqrt(15))