What is the foci 9x^2+25y^2+18x+50y-191=0 ?

The foci 9x^2+25y^2+18x+50y-191=0 is (3,-1),(-5,-1)

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foci 9x^2+25y^2+18x+50y-191=0

foci

9 x^{2} + 25 y^{2} + 18 x + 50 y - 191 = 0

(3, - 1), (- 5, - 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 18 x + 50 y - 191 = 0 :

Ellipse with center

(h, k) = (- 1, - 1), a = 5, b = 3

(- 1 + c, - 1), (- 1 - c, - 1)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 1 + 4, - 1), (- 1 - 4, - 1)

Refine

(3, - 1), (- 5, - 1)

3 x^{2} + 4 y^{2} - 16 x + 16 = 0

3 x^{2} - 6 x + y^{2} + 4 y - 11 = 0

5 x^{2} + 2 y^{2} = 5

4 x^{2} + 8 x + 2 y^{2} + 16 y = - 28

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

What is the foci 9x^2+25y^2+18x+50y-191=0 ?
The foci 9x^2+25y^2+18x+50y-191=0 is (3,-1),(-5,-1)