What is the foci 3x^2+4y^2-16x+16=0 ?

The foci 3x^2+4y^2-16x+16=0 is (10/3 ,0),(2,0)

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foci 3x^2+4y^2-16x+16=0

foci

3 x^{2} + 4 y^{2} - 16 x + 16 = 0

(\frac{10}{3}, 0), (2, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

3 x^{2} + 4 y^{2} - 16 x + 16 = 0 :

Ellipse with center

(h, k) = (\frac{8}{3}, 0), a = \frac{4}{3}, b = \frac{2}{3}

(\frac{8}{3} + c, 0), (\frac{8}{3} - c, 0)

Compute

c :

c = (\frac{4}{3})^{2} - (\frac{2}{3})^{2} : \frac{2}{3}

(\frac{8}{3} + \frac{2}{3}, 0), (\frac{8}{3} - \frac{2}{3}, 0)

Refine

(\frac{10}{3}, 0), (2, 0)

3 x^{2} - 6 x + y^{2} + 4 y - 11 = 0

5 x^{2} + 2 y^{2} = 5

4 x^{2} + 8 x + 2 y^{2} + 16 y = - 28

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

\frac{( x + 1 ) ^{2}}{1} + \frac{( y - 2 ) ^{2}}{4} = 1

What is the foci 3x^2+4y^2-16x+16=0 ?
The foci 3x^2+4y^2-16x+16=0 is (10/3 ,0),(2,0)