What is the foci 25x^2+81y^2=2025 ?

The foci 25x^2+81y^2=2025 is (2sqrt(14),0),(-2sqrt(14),0)

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foci 25x^2+81y^2=2025

foci

25 x^{2} + 81 y^{2} = 2025

(214, 0), (- 214, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

25 x^{2} + 81 y^{2} = 2025 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 5^{2} : 214

(0 + 214, 0), (0 - 214, 0)

Refine

(214, 0), (- 214, 0)

x^{2} + 9 y^{2} - 14 x + 36 y + 49 = 0

4 x^{2} - 24 x + \frac{y ^{2}}{16} + \frac{y}{8} + \frac{573}{16} = 0

\frac{( x + 5 ) ^{2}}{5} + \frac{( y + 9 ) ^{2}}{9} = 1

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{9} = 1

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0

What is the foci 25x^2+81y^2=2025 ?
The foci 25x^2+81y^2=2025 is (2sqrt(14),0),(-2sqrt(14),0)