What is the foci 16x^2+9y^2-96x+36y-36=0 ?

The foci 16x^2+9y^2-96x+36y-36=0 is (3,-2+sqrt(21/2)),(3,-2-sqrt(21/2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 16x^2+9y^2-96x+36y-36=0

foci

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0

(3, - 2 + \frac{21}{2}), (3, - 2 - \frac{21}{2})

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0 :

Ellipse with center

(h, k) = (3, - 2), b = 26, a = \frac{3 3}{2}

(3, - 2 + c), (3, - 2 - c)

Compute

c :

c = (26)^{2} - (\frac{3 3}{2})^{2} : \frac{21}{2}

(3, - 2 + \frac{21}{2}), (3, - 2 - \frac{21}{2})

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

4 x^{2} + 8 y^{2} = 3

16 x^{2} + 4 y^{2} - 64 = 0

\frac{( x + 6 ) ^{2}}{7} + \frac{( y - 3 ) ^{2}}{16} = 1

What is the foci 16x^2+9y^2-96x+36y-36=0 ?
The foci 16x^2+9y^2-96x+36y-36=0 is (3,-2+sqrt(21/2)),(3,-2-sqrt(21/2))