What is the foci 25x^2+4y^2-100=0 ?

The foci 25x^2+4y^2-100=0 is (0,sqrt(21)),(0,-sqrt(21))

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foci 25x^2+4y^2-100=0

foci

25 x^{2} + 4 y^{2} - 100 = 0

(0, 21), (0, - 21)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 4 y^{2} - 100 = 0 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 2^{2} : 21

(0, 0 + 21), (0, 0 - 21)

Refine

(0, 21), (0, - 21)

\frac{x ^{2}}{1.586 9 ^{2}} + \frac{y ^{2}}{0.9989} = 1

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

\frac{( x + 7 ) ^{2}}{90} + \frac{( y + 8 ) ^{2}}{84} = 1

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

\frac{x ^{2}}{27} + \frac{y ^{2}}{36} = 1

What is the foci 25x^2+4y^2-100=0 ?
The foci 25x^2+4y^2-100=0 is (0,sqrt(21)),(0,-sqrt(21))