What is the foci (x^2)/(96)+(y^2)/(100)=1 ?

The foci (x^2)/(96)+(y^2)/(100)=1 is (0,2),(0,-2)

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foci (x^2)/(96)+(y^2)/(100)=1

foci

\frac{x ^{2}}{96} + \frac{y ^{2}}{100} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{96} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 46

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 0^{2} - (46)^{2} : 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

9 x^{2} + 25 y^{2} - 100 y - 125 = 0

3 x^{2} + 4 y^{2} = 12

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

What is the foci (x^2)/(96)+(y^2)/(100)=1 ?
The foci (x^2)/(96)+(y^2)/(100)=1 is (0,2),(0,-2)