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Popular >

foci 3x^2+4y^2=12

Solution

foci

3 x^{2} + 4 y^{2} = 12

Solution

(1, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

3 x^{2} + 4 y^{2} = 12 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} - 3^{2} : 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

Popular Examples

foci ((x-1)^2}{16}+\frac{(y+2)^2)/9 =1 foci

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

foci ((x-3)^2}{25}+\frac{(y+1)^2)/9 =1 foci

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

foci 9x^2+16y^2-36x+96y+36=0 foci

9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

foci ((x-1)^2)/(45)+(y^2)/(54)=1 foci

\frac{( x - 1 ) ^{2}}{45} + \frac{y ^{2}}{54} = 1

foci 36x^2+5y^2-90y-495=0 foci

36 x^{2} + 5 y^{2} - 90 y - 495 = 0

Frequently Asked Questions (FAQ)

What is the foci 3x^2+4y^2=12 ?
The foci 3x^2+4y^2=12 is (1,0),(-1,0)