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Beliebt Geometry >

leitkurve y=-4x^2

Lösung

leitkurve

y = - 4 x^{2}

Lösung

y = \frac{1}{16}

Schritte zur Lösung

Rewrite

y = - 4 x^{2}

in the standard form:

4 (- \frac{1}{16}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{16}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{16})

Fasse zusammen

y = \frac{1}{16}

Graph

Beliebte Beispiele

scheitelpunkte (x^2}{25}-\frac{y^2)/9 =1

v er t i ces \frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} - 2 x - 4 y + 9 = 0

4 x^{2} + 25 y^{2} = 100

leitkurve x^2=4y

d i rec t r i x x^{2} = 4 y

x^{2} = - 16 y