What is the vertices (x^2)/(96)+(y^2)/(100)=1 ?

The vertices (x^2)/(96)+(y^2)/(100)=1 is (0,10),(0,-10)

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vertices (x^2)/(96)+(y^2)/(100)=1

vertices

\frac{x ^{2}}{96} + \frac{y ^{2}}{100} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{96} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 46

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

\frac{( x + 4 ) ^{2}}{24} + \frac{( y + 2 ) ^{2}}{49} = 1

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{4} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{9} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{49} = 1

9 x^{2} + 81 y^{2} - 729 = 0

What is the vertices (x^2)/(96)+(y^2)/(100)=1 ?
The vertices (x^2)/(96)+(y^2)/(100)=1 is (0,10),(0,-10)