What is the vertices ((x+4)^2)/(24)+((y+2)^2)/(49)=1 ?

The vertices ((x+4)^2)/(24)+((y+2)^2)/(49)=1 is (-4,5),(-4,-9)

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vertices ((x+4)^2)/(24)+((y+2)^2)/(49)=1

vertices

\frac{( x + 4 ) ^{2}}{24} + \frac{( y + 2 ) ^{2}}{49} = 1

(- 4, 5), (- 4, - 9)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x + 4 ) ^{2}}{24} + \frac{( y + 2 ) ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (- 4, - 2), b = 7, a = 26

(- 4, - 2 + 7), (- 4, - 2 - 7)

Refine

(- 4, 5), (- 4, - 9)

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{4} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{9} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{49} = 1

9 x^{2} + 81 y^{2} - 729 = 0

16 x^{2} + 4 y^{2} = 64

What is the vertices ((x+4)^2)/(24)+((y+2)^2)/(49)=1 ?
The vertices ((x+4)^2)/(24)+((y+2)^2)/(49)=1 is (-4,5),(-4,-9)