What is the vertices 4x^2+25y^2=100 ?

The vertices 4x^2+25y^2=100 is (5,0),(-5,0)

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vertices 4x^2+25y^2=100

vertices

4 x^{2} + 25 y^{2} = 100

(5, 0), (- 5, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 25 y^{2} = 100 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 2

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0

3 x^{2} + 12 y^{2} - 6 x - 48 y + 33 = 0

36 x^{2} + 25 y^{2} = 900

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

x^{2} + y^{2} + 8 x = 32

What is the vertices 4x^2+25y^2=100 ?
The vertices 4x^2+25y^2=100 is (5,0),(-5,0)