What is the vertices 36x^2+25y^2=900 ?

The vertices 36x^2+25y^2=900 is (0,6),(0,-6)

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vertices 36x^2+25y^2=900

vertices

36 x^{2} + 25 y^{2} = 900

(0, 6), (0, - 6)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

36 x^{2} + 25 y^{2} = 900 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 5

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

x^{2} + y^{2} + 8 x = 32

4 x^{2} + 9 y^{2} - 16 x + 36 y + 16 = 0

25 x^{2} + 81 y^{2} = 2025

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

What is the vertices 36x^2+25y^2=900 ?
The vertices 36x^2+25y^2=900 is (0,6),(0,-6)