What is the vertices (x^2)/(63500)+(y^2)/(50900)=1 ?

The vertices (x^2)/(63500)+(y^2)/(50900)=1 is (10sqrt(635),0),(-10sqrt(635),0)

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vertices (x^2)/(63500)+(y^2)/(50900)=1

vertices

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

(10635, 0), (- 10635, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10635, b = 10509

(0 + 10635, 0), (0 - 10635, 0)

Refine

(10635, 0), (- 10635, 0)

3 x^{2} + y^{2} = 84

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

9 x^{2} + 4 y^{2} + 72 x - 40 y + 208 = 0

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

What is the vertices (x^2)/(63500)+(y^2)/(50900)=1 ?
The vertices (x^2)/(63500)+(y^2)/(50900)=1 is (10sqrt(635),0),(-10sqrt(635),0)