What is the vertices ((x^2)/(15))+((y^2)/(16))=1 ?

The vertices ((x^2)/(15))+((y^2)/(16))=1 is (0,4),(0,-4)

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vertices ((x^2)/(15))+((y^2)/(16))=1

vertices

(\frac{x ^{2}}{15}) + (\frac{y ^{2}}{16}) = 1

(0, 4), (0, - 4)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{15} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 15

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

9 x^{2} - 36 x + 4 y^{2} = 0

x^{2} + 4 y^{2} = 4

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

8 x^{2} + 2 y^{2} + 16 x = 0

9 X^{2} + 4 Y^{2} = 36

What is the vertices ((x^2)/(15))+((y^2)/(16))=1 ?
The vertices ((x^2)/(15))+((y^2)/(16))=1 is (0,4),(0,-4)